๐ Every order divides 1023
The order of any nonzero element of GF(1024) divides $1023 = 3 \\\\cdot 11 \\\\cdot 31$, so it is one of 1, 3, 11, 31, 33, 93, 341, 1023.
Proof: See the collapsible proof in the section itself, where it is presented in full.
From: codex32
Learn more:
Explore all courses: 

Magic Internet Math
Interactive courses covering the mathematics that powers modern technology, from foundational algebra to the cryptography securing the internet.

Magic Internet Math
Interactive courses covering the mathematics that powers modern technology, from foundational algebra to the cryptography securing the internet.