Replies (19)

it's easy 🀣 def block_url_spam(x): z=x['content'] for j in z.split(): if j[0:5]=="https": if len(x['content'])==len(j) or len(x['content'])+5==len(j): return "no context" else: return codifica_link(x)
you can put lipstick on a pig but you can't make a language syntax readable without thinking a lot about it. python isn't as ugly as rust, so there's some upsides to python.
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